The horizontal range of a projectile fired at an angle of `15^(@)` is `50m`. If it is fired with the same speed, what is the maximum range that can be obtained?

The range of a projectile fired at an angle of 15^@ is 50 m. If it is fired with the same speed at an angle of 45^@ its range will be

The range of a projectile fired at an angle of 15^@ is 50 m. If it is fired with the same speed at an angle of 45^@ its range will be

The range of a projectile fired at an angle of 15^@ is 50 m. If it is fired with the same speed at an angle of 45^@ its range will be

The range of a projectile fired at an angle of 15^@ is 50 m. If it is fired with the same speed at an angle of 45^@ its range will be

The range of a projectile, when launched at an angle of 15^(@) with the horizontal is 1.5 km. what is the range of the projectile, when launched at an angle of 45^(@) to the horizontal with the same speed ?

The horizontal range of a projectile is 2 sqrt(3) times its maximum height. Find the angle of projection.

The horizontal range of projectile is 4sqrt(3) times the maximum height achieved by it, then the angle of projection is

A projectile thrown with an initial speed u and the angle of projection 15^@ to the horizontal has a range R . If the same projectile is thrown at an angle of 45^@ to the horizontal with speed 2 u , what will be its range ?

The range of a projectile launched at an angle of 15^(@) with horizontal is 1.5km. The range of projectile when launched at an angle of 45^(@) to the horizontal is

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is