If `A:{0,pi/6,pi/4,pi/3,pi/2}` and `f:A->B` is a surjection defined by `f(x)=cosx` then find `B`.

If A={0 , pi/6, pi/4, pi/3, pi/2} and f: A rarr B is a surjection defined by fx) = cosx then find B

" 07.If "A={0(k)/(6),(pi)/(4)*(pi)/(3),(pi)/(2)}" and "f:A rarr B,f(x)=cos x" is surjection find "B

The function f defined by f(x)=(4sinx-2x-xcosx)/(2+cosx),0lexle2pi is :

If f(x)=|cosx|, then f'((3 pi)/(4)) equal to

Let f(x)=(1-tan x)/(4x-pi),x!=(pi)/(4),x in[0,(pi)/(2)], If f(x) is continuous in [0,(pi)/(4)], then find the value of f((pi)/(4))

Find alpha and beta, so the function f (x) defined by f(x) =-2 sin x, "for" -pi le x le-pi/2 =alpha sinx+beta"for" -pi/2lt x lt pi/2 =cosx , "for" pi/2 le x le pi, is continuous on [-pi, pi].

If f(x) = |cosx| , then f'(pi/4) is equal to "……."