The velocity of a particle moving along `x`-axis can be given by relation `V=2x` where `x` is the position of particle on `x`-axis. Find the acceleration of the particle when particle is at `x=3m`

The velocity of a particle moving along x-axis is given as v=x^(2)-5x+4 (in m // s) where x denotes the x-coordinate of the particle in metres. Find the magnitude of acceleration of the particle when the velocity of particle is zero?

The position of a particle moving along x- axis is given by x=x_0 cos^2(omegat) . Its when it is at mean position is

The speed v of a particle moving along a straight line is given by a+bv^(2)=x^(2) where x is its distance from the origin. The acceleration of the particle is

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.

x-t equation of a particle moving along x-axis is given as x=A+A(1-cosomegat)

The velocity of a particle moving in the positive direction of X-axis varies as v=5sqrt(x) . Assuming that at t = 0, particle was at x = 0. What is the acceleration of the particle ?

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

If v = x^2 - 5x + 4 , find the acceleration of the particle when velocity of the particle is zero.

The velocity of a particle moving on the x-axis is given by v=x^(2)+x , where x is in m and v in m/s. What is its position (in m) when its acceleration is 30m//s^(2) .

The potential energy U(x) of a particle moving along x - axis is given by U(x)=ax-bx^(2) . Find the equilibrium position of particle.