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Electrolysis of water can be used as a m...

Electrolysis of water can be used as a method of preparation of oxygen and hydrogen gas. In an experiment 22.4mL/s, oxygen required. How much current has to supplied to carry out the experiment at STP?

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When the electrolysis of acidified water is carried out : (a) What is the ratio of the volume of hydrogen produced to the volume of oxygen ? Give the equation for the discharge of ions at the two electrodes .

In an electrolysis of acidulated water, 4.48 L of hydrogen at STP was produced by passing a current of 2.14 A. For how many hours was the current passed ?

During the electrolysis of water, a total volume of 33.6mL of hydrogen and oxygen gas was collected at STP . Find the amound of electricity that passed during electrolysis.

A vessel having certain amount of oxygen at certain pressure and temperature develops a very small hole and 4 g of oxygen effuses out. How much hydrogen would have effused out of the same vessel had it been taken at the same pressure and temperature.

Oxygen differs from the other elements of the group. Compounds of oxygen with metals are more ionic in nature and hydrogen bonding is more important for oxygen compounds. Oxygen is never more than divalent beacasue when it hs formed two covalent bonds, there are no low energy orbitals which can be used for form. further bonds. However, the elements S,Se,Te and Po have empty d- orbitals which may be used for bonding, and they can form four or six bonds by unpairing electrons. The higher oxidation states become less stable on decending the group. The bond between S and O, or Se and O, are much shorter than might be expected for a single bond owing to rho pi - dpi interaction between the p- orbital of oxygen and d- orbital of S or Se. Which of the following statemet is incorrect ?

Oxygen differs from the other elements of the group. Compounds of oxygen with metals are more ionic in nature and hydrogen bonding is more important for oxygen compounds. Oxygen is never more than divalent beacasue when it hs formed two covalent bonds, there are no low energy orbitals which can be used for form. further bonds. However, the elements S,Se,Te and Po have empty d- orbitals which may be used for bonding, and they can form four or six bonds by unpairing electrons. The higher oxidation states become less stable on decending the group. The bond between S and O, or Se and O, are much shorter than might be expected for a single bond owing to rho pi - dpi interaction between the p- orbital of oxygen and d- orbital of S or Se. Which one of the following orders represents the correct order for the properties indicated against them?

The following materials are provided - solutions of cobalt chloride, ammonia, potassium permanganate, lime water, starch-iodide, sodium hydroxide, lead acetate, potassium iodide. Also provided are litmus and filter papers, glowing splinters and glass rods. Using the above how would you distinguish between: a] a neutral, acidic and a basic gas b] oxygen and hydrogen gas. c] carbon dioxide and sulphur dioxide gas d] chlorine and hydrogen chloride gas e) hydrogen sulphide and nitrogen dioxide gas f] ammonia and carbon dioxide gas g] zinc carbonate and potassium nitrate h] hydrated copper sulphate and anhydrous copper sulphate i] ammonium sulphate and sodium sulphate.

In order to get maximum calorific output a burner should have an optimum fuel to oxygen ratio which corresponds to three times as much oxygen as is required theorectically for complete combusion of the fuel A burner which has been adjused for methane as fuel (with x L h^(-1) of CH_(4) and 6x Lh^(-1) of CO_(2)) is to be readjusted for butane C_(4)H_(10) in order to get the same calorific output what should be the rate of supply to butane and oxygen? Assume that losses due to incomplete combustion etc are the same for both fuels and that the gases behave ideally Heats of combusion CH_(4) =809 kJ mol^(-1),C_(4)H_(10) =2878 kJmol^(-1) .

In order to get maximum calorific output a burner should have an optimum fuel to oxygen ratio which corresponds to three times as much oxygen as is required theorectically for complete combusion of the fuel A burner which has been adjused for methane as fuel (with x L h^(-1) of CH_(4) and 6x Lh^(-1) of CO_(2)) is to be readjusted for butane C_(4)H_(10) in order to get the same calorific output what should be the rate of supply to butane and oxygen? Assume that losses due to incomplete combustion etc are the same for both fuels and that the gases behave ideally Heats of combusion CH_(4) =809 kJ mol^(-1),C_(4)H_(10) =2878 kJmol^(-1) .

A thermal power plant produed electric power of 600kW at 4000V, which is to be transported to a place 20 km away form the power plant for consumer's usage. It can be transported either directly with a cable of large current carrying capacity or by sing a combination of step-up and step-down transfprmers at the two ends. THe drawback of the direct transmission is the large energy dissipation. In the method wsing transformers, the dissipatiion is much smaller. In this method a step-up transformers is used at the plant side so that the current is reduced to a smaller value. At the consumers'end, a step-down transformer is used to supply power to the consumers at the specified lower voltage. It is reasonable to assume that the power cable is purely resostive and the transformers are ideal with power factor unity. All the currents and voltagementioned are values. In the method using the transformers assume that the ratio of the number of turns in the primary to that in the secondary in the step-up transformer is 1:10 if the power to the consumers has to be supplied at 200V, the ratio of the number of turns in the primary to that in the secondary in the step-down transformer is