If 2f(sin x)+f(cos x)=x `AA x in R` then range of f(x) is `[(-pi)/(3),(pi)/(3)]`,`[(-2 pi)/(3),(pi)/(3)]`,`[[(-2 pi)/(3),(pi)/(6)]],[[(-pi)/(6),(pi)/(6)]]`

The range of f(x)=sin^(-1)(sqrt(x^(2)+x+1)) is (0,(pi)/(2))(b)(0,(pi)/(3))(c)((pi)/(3),(pi)/(2)) (d) [(pi)/(6),(pi)/(3)]

The range of f(x)=sin^(3)x in domain [-(pi)/(2),(pi)/(2)] is

Range of function f(x)=arccot(2x-x^(2)) is [(pi)/(4),(3 pi)/(3)](b)[0,(pi)/(4)][0,(pi)/(2)] (d) [(pi)/(4),pi]

The solutions of the equation sin x+2sin2x+sin3x=cos x+3cos2x+cos3x in the interval 0<=x<=2 pi, are (pi)/(8),(5 pi)/(8),(2 pi)/(3)(b)(pi)/(8),(5 pi)/(8),(9 pi)/(8),(13 pi)/(8)(1 pi)/(3),(9 pi)/(3),(2 pi)/(3),(13 pi)/(8) (d) (pi)/(8),(5 pi)/(8),(9 pi)/(3),(4 pi)/(3),(4 pi)/(3),(9 pi)/(3),(2 pi)/(3),(13 pi)/(8)(d)

1+sinx + sin^2(x) + .... = 4+2sqrt3, 0ltxltpi, x!=pi, then x = 1) (pi)/(3), (pi)/(4) 2) (pi)/(4), (pi)/(6) 3) (2 pi)/(5), (pi)/(6) 4) (pi)/(3), (2 pi)/(3)

find the range of function f(x)=sin(x+(pi)/(6))+cos(x-(pi)/(6))

If f:F rarr R is defind by f(x)=7+cos(5x+3),AA x in R then period of f is (A)2 pi(B)pi(C)(pi)/(5) (D) 2(pi)/(5)

The range of f(x)=sin^(-1)((x^(2)+1)/(x^(2)+2)) is [0,(pi)/(2)] (b) (0,(pi)/(6))( c) [(pi)/(6),(pi)/(2)](d) none of these

The range of f(x)=cot^(-1)(log_(1/2)(x^(4)-2x^(2)+3)) is ( (pi)/(2) (3 pi)/(4) 0 (3 pi)/(4) pi) (0 (3 pi)/(4)

f(x)=min(sin x,cos x),x in(-pi,pi) the values of x where f(x) is non differentiable,is the set A. Then A is subset of (A) {(-3 pi)/(4),(-pi)/(4),(3 pi)/(4)}(B){(-pi)/(4),(pi)/(4),(3 pi)/(3)}(C){(-3 pi)/(4),(3 pi)/(4)}(D){(-3 pi)/(4),(pi)/(4),(pi)/(4),(3 pi)/(4)}