A ball is dropped from the top of a tower when there is a high speed wind.If the wind exerts a constant force on the ball,the path traced by the ball is

High speed wind blows over a house. The force on the roof is

A ball is dropped from the top of a tower of height 78.4 m Another ball is thrown down with a certain velocity 2 sec later. If both the balls reach the ground simultaneously, the velocity of the second ball is

A ball is dropped from a height of 49 m. The wind is blowing horizontally. Due to wind a constant horizontal acceleration is provided to the ball. Choose the correct statement (s).

A ball is dropped from a height of 49 m. The wind is blowing horizontally. Due to wind a constant horizontal acceleration is provided to the ball. Choose the correct statement (s).

A ball is dropped from the top of a tower of herght (h). It covers a destance of h // 2 in the last second of its motion. How long does the ball remain in air?

A ball is dropped from rest from a tower of height 5m. As a result of the wind it lands at a distance 6m from the bottom of the tower as shown. Assuming no air resistance but that the wind gives the ball a constant horizonta velocity v. Find value of v in m/s.

A ball is thrown from a point in level with velocity u and at a horizontal distance r from the top os a tower of height h . How must the speed and angle of the projection of the ball be related to r in order that the ball may just go grazing the top edge of the tower ?

A ball is dropped from the top of a 200 m high tower on a planet. In the last 1/2 s before hitting the ground, it covers a distance of 79 m. Acceleration due to gravity (in ms–2) near the surface on that planet is ______.

A ball is dropped from the top of a tower. In the last second of motion it covers (5)/(9) th of tower height before hitting the ground. Acceleration due to gravity = 10 (in ms^(–2)) . Find height of tower (in m):

A ball is dropped from the top of a tower. In the last second of motion it covers (5)/(9) th of tower height before hitting the ground. Acceleration due to gravity = 10 (in ms^(–2)) . Find height of tower (in m):