Two point charges of magnitude `4 mu C` and `-9 mu C` are 0.5m apart.The electric intensity is zero at a distance x m from `+4 mu C`.Then x is

Two positive point charges of 12 mu C and 8 mu C are 10 cm apart. The work done in bringing then 4 cm closer is

Two positive point charges of 12 mu C and 8 mu C are 10 cm apart. The work done in bringing then 4 cm closer is

Two point electric charges of unknown magnitudes and signs are placed a certain distance apart. The electric field intensity is zero at a point not between the charges but on the line joining them. Write two essential conditions for this to happen.

Two point charges of 20 mu C and 80 muC are 10 cm apart where will the electric field strength be zero on the line joining the charges from 20 mu C charge

Two charges +20 mu C and - 20 muC are 5 mm apart. Find the electric field on axial as well as on the equatorial line at a distance 20 cm from the mid -point of the dipole.

Two electric charges 12 mu C and -6 mu C are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from 6 mu C charge is

A and B are two points separately by a distance 5cm. Two charges 10 mu C and 20mu C are placed at A and B. The resultant electric intensity at a point P outside the charges at a distance 5cm from 10 mu C is

Two point charges +5xx10^(-19)C and +20xx10^(-19)C are separated by a distance of 2m. The electric field intensity will be zero at a distance d=………. From the charges of 5xx10^(19)C .

Two electric charges of 9 mu C and -3 mu C are placed 0.16 m apart in air. There will be a point P at which electric potential is zero on the line joining two charges and in between them. The distance of P from 9 mu C is

Two charges +5mu C and +10 mu C are placed 20 cm apart. The net electric field at the mid-point between the two charges is