If `2%` of the main current is to be passed through the galvanometer of resistance `G`, the resistance of shunt required is

If only one hundredth part of total current flowing in the circuit is to be passed through a galvanometer of resistance G Omega , Then the value of shunt resistance required will be-

In a ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G , the resistance of ammeter will be

A galvanometer has a resistance of 98Omega . If 2% of the main current is to be passed through the meter what should be the value of the shunt?

To send 10% of the main current through a moving coil galvanometer of resistance 99Omega , the shunt required is –

A galvanometer of resistance 150 ohm is shunted such that only 1/11 of the main current flows through the galvanometer. The resistance of the shunt is, (in ohm)

To send 10% of the main current through a moving coil galvanometer of resistance 9 Omega , shunt S required is

A maximum current of 0.5 mA can be passed through a galvanometer of resistance 20Omega . Calculate the resistance to be connected in series to convert it into a voltmeter of range (0- 5)V .

A moving coil galvnometer is converted into an ammeter reading up to 0.03 A by connecting a shunt of resistance r/4 . What is the maximum current which can be sent through this galvanometer if no shunt is used (here r=resistance of galvanometer)

A moving coil galvanometer has a resistance of 990Omega. in order to send only 10% of the main currect through this galvanometer, the resistance of the required shunt is

In a galvanometer 5% of the total current in the circuit passes through it. If the resistance of the galvanometer is G, the shunt resistance 'S' connected to the galvanometer is