A particle is executing S.H.M.of time period 4 seconds.What time will its take in going from y=0 to y=amplitiude

A particle executing SHM with time period of 2 s : Find the time taken by it to move from one amplitude to half the amplitude position.

A particle executes linear SHM with time period of 12 second. Minimum time taken by it to travel from positive extreme to half of the amplitude is

A particle undergoes S.H.M. having time period T . The time taken in 3 /8th oscillation is

A particle is executing SHM with time period T Starting from mean position, time taken by it to complete (5)/(8) oscillations is,

A particle executes S.H.M with time period 12 s. The time taken by the particle to go directly from its mean position to half its amplitude.

A particle executes SHM with a time period of 4 s . Find the time taken by the particle to go from its mean position to half of its amplitude . Assume motion of particle to start from mean position.

A paricle performs S.H.M. with time period T . The time taken by the particle to move from hall the amplitude to the maximum dispalcement is T/2

A particle is executing SHM with time period T. If time period of its total mechanical energy isT' then (T')/(T) is

A particle executes SHM of period 1.2 s and amplitude 8cm . Find the time it takes to travel 3cm from the positive extremity of its oscillation. [cos^(-1)(5//8) = 0.9rad]

The figure shows the displacement-time graph of a particle executing SHM . If the time period of oscillation is 2s , then the equation of motion is given by