Simplify `sqrt(m^(2)n^(2)` + `root(6)(m^(2)n^(2))` + `root(3)(m^(2)n^(2))`

sqrt(m^(2)n^(2))times root(6)(m^(2)n^(2))times root(3)(m^(2)n^(2))

(m^(2)-n^(2))^(2)+2m^(2)n^(2)

Simplify 2m(5m+4n)

Simplify: (6m-n)(36m^(2)+6mm+n^(2))(3m+2n)^(3)

Simplify: (2.5p-1.5q)^(2)-(1.5p-2.5q)^(2)(m^(2)-n^(2)m)^(2)+2m^(3)n^(2)

Simplify: (16m^(3)y^(2))/(4m^(2)y)(2)(32m^(2)n^(3)p^(2))/(4mnp)

If sintheta=(m^(2)-n^(2))/(m^(2)+n^(2)) , then tantheta=?

The distance between the points (m,-n) and (-m,n) is (A) sqrt(m^2 + n^2) (B) m+n (C) 2 sqrt(m^2+n^2) (D) sqrt(2m^2 +2n^2)

The roots of the equation l^(2)(m^(2)-n^(2))x^(2)+m^(2)(n^(2)-l^(2))x+n^(2)(I^(2)-m^(2))=0 are