A steel rod is projecting out of rigid wall.The shearing strength of steel is `345MN/m^(2)` . The dimensions AB=5cm,BC=BE=2cm .The maximum load that can be put on the face "ABCD" is (neglect bending of the rod) `(g=10m/s^(2))`

A) 3450kg

B) 1380kg

C) 13800kg

D) 345kg

A steel cable with a radius of 1.5 cm support a chairlift at a ski area.if the maximum stress is not to exceed 10^(8) Nm^(-2) , what is the maximum load the cable can support?

A steel cable with a radius 2 cm supports a chairlift at a ski area. If the maximum stress is not to exceed 10^8 N m^(-2) , the maximam load the cable can support

The breaking stress of steel is 7.85 xx 10^(8) N//m^(2) and density of steel is 7.7 xx 10^(3) kg//m^(3) . The maximum frequency to which a string 1 m long can be tuned is

A rod OA of mass 4 kg is held in horizontal position by a massless string AB as shown in figure. Length of the rod is 2 m . Find (a) tension in the string (b) net force exerted by hings on the rod. (g = 10 m//s^(2))

A 10 kg steel ball is suspended by two strings as shown. The tensions in the two strings are: (g=9.8 m//s^(2) )

The two wires shown in figure are made of the same material which has a breaking stress of 8xx10^8Nm^-2 . The area of cross section of the upper wire is 0.006 cm^2 and that of the lower wire is 0.003 cm^2 . The mass m_1=10 kg , m_2=20kg and the hanger is light. a. Find the maximum load that can be put on the hanger without breaking a wire. Which wire will break first if the load is increased? b. Repeat the above part m_1=10 kg and m_2=36kg .

A steel rod 2.0 m long has a cross-sectional area of 0.30cm^(2) . The rod is now hung by one end from a support structure, and a 550 kg milling machine is hung from the strain, and the elongation of the rod.

A 2kg brick of dimension 5cm xx 2.5 cm xx 1.5 cm is lying on the largest base. It is now made to stand with length vertical, then the amount of work done is : (taken g=10 m//s^(2) )

In a smooth hemispherical shell of radius R, a rod of mass (sqrt3//2) kg is placed horizotally and is in equilibrium. The length of rod is R. Find the normal reaction at any end of the rod (in N). (Take g=10m//s^(2))

The area of base of a cylindrical vessel is 300 "cm"^2 . Water (density= 1000 "kg/m"^3 ) is poured into it up to a depth of 6 cm. Calculate the thrust of water on the base. (g = 10 "m s"^(-2)) .