If `x sin theta-y cos theta`=`sqrt(x^(2)+y^(2))" and "(cos^(2)theta)/(a^(2))+(sin^(2)theta)/(b^(2))=(1)/(x^(2)+y^(2)),` then

cos theta sqrt(1-sin^(2)theta)=

The roots of the equation |(3x^(2),x^(2) + x cos theta + cos^(2) theta ,x^(2) + x sin theta + sin^(2) theta),(x^(2) + x cos theta + cos^(2) theta,3 cos^(2) theta,1 + (sin 2 theta)/(2)),(x^(2) + x sin theta + sin^(2) theta,1 + (sin 2 theta)/(2),3 sin^(2) theta)| = 0

cos2 theta*cos(theta/(2))-cos3 theta*cos((9theta)/2)=sin5 theta*sin((5theta)/(2))

If x = a cos theta and y = bcot theta, show that : (a^(2))/(x^(2)) - (b^(2))/ (y^(2)) = 1

If cos ^(-1)\ (x)/(a) + cos^(-1)\ (y)/(b) = theta , then (x^(2))/(a^(2)) +(y^(2))/(b^(2))=?

If x =2 cos theta - cos 2 theta y = 2 sin theta - sin 2 theta Find (d^(2)y)/(dx^(2)) at theta = pi/2

If cos theta + sin theta =sqrt(2) cos theta prove that cos theta -sin theta =sqrt(2) sin theta

If x = a cos^(3) theta, y = a sin ^(3) theta then sqrt(1+((dy)/(dx))^(2)) =?

If f(x)=|{:( sin^2 theta , cos^(2) theta , x),(cos^(2) theta , x , sin^(2) theta ),( x , sin^(2) theta , cos^2 theta ):}| theta in (0,pi//2), then roots of f(x)=0 are

(2 sin theta*cos theta - cos theta)/(1-sin theta+sin^2 theta-cos^2 theta) = cot theta