An excited `He^(+)` ion emits two photons in succession with wavelengths 108.5nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength `lamda` energy
`E=(1240eV)/(lamda("in cm"))`

He^(+) is in n^(th) state. It emits two successive photons of wavelength 103.7nm and 30.7nm , to come to ground state the value of n is:

An excited state of H atom emits a photon of wavelength lamda and returns in the ground state. The principal quantum number of excited state is given by:

An excited He^(+) ion emits photon of wavelength lambda in returning to ground state from n^(th) orbit. If R is Rydberg's constant then :

A 100 eV electron collides with a stationary helium ion (He^(+)) in its ground state and excites to a higher level. After the collision , He^(+) ion emits two photons in succession with wavelength 1085 Å and 304 Å . Find the principal quantum number of the excite in its ground state and. Also calculate energy of the electron after the collision. Given h = 6.63 xx 10^(-34) J s .

An excited hydrogen atom emits a photon of wavelength lambda in returning to the ground state. If 'R' is the Rydberg's constant, then the quantum number 'n' of the excited state is:

An excited hydrogen atom emits a photon of wavelength lambda in returning to the ground state. If 'R' is the Rydberg's constant, then the quantum number 'n' of the excited state is:

A photon of energy 12.09 eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of excited state is

A hydrogen atom ia in excited state of principal quantum number n . It emits a photon of wavelength lambda when it returnesto the ground state. The value of n is

Find the quantum of the excited state of electrons in He^(+) ion which on transition to first excited state emit photons of wavelengths 108.5 nm . (R_(H)=1.09678xx10^(7) m^(-1))

The energy of a hydrogen atom in its ground state is -13.6 eV . The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is