An object is projected upwards with a velocity of 100m/s. It will strike the ground after___sec(g=10m/`s^(2)`)

An object is thrwon vertically upwards with a velocity of 60 m/s. After what time it strike the ground ? Use g=10m//s^(2) .

A ball is projected from a point O as shown in figure it will strike the ground after (g = 10 m/ s^(2) )

A particle P is projected upwards with 80m//s . One second later another particle Q is projected with initial velocity 70m//s . Before either of the particle srikes the ground (g=10m//s^(2))

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2)) (a) 15m//s (b) 20 m//s (c) 25m//s (d) 28 m//s

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

At t = 0 source starts falling under gravity and a detector is projected upwards with a velocity 10m/s. For the vertical upward motion of detector

A particle is projected upwards with a velocity of 100 m//s at an angle of 60^(@) with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g = 10 m//s^(2) .

A ball is projected vertically up wards with a velocity of 100 m/s. Find the speed of the ball at half the maximum height. (g=10 m//s^(2))

A body is projected horizontally from the top of a tower with a velocity of 10m/s. If it hits the ground at an angle of 45^@ , the vertical component of velocity when it hits ground in m/s is