Std-10 Most Imp Ch 6 Gseb L-19 જૈવિક ક્રિયાઓ

5, 6, 10, 19, 35 ?

Valence Bond Theory -C.N.=6,all Possible Cases OF Para and dia in C.N.-4 and 6 (Most Imp) || Transfer OF Electron in Complex OF C.N. and C.N.-6

The charge on a proton is +1.6 X 10(-19) C and that on an . electron is -1.6 X 10 (-19)C. Does it mean that the electron . has a charge 3.2 X 10(-19) c less than the charge of a . proton?

A photoelectron is moving with a maximum velocity of 10^(6) m//s . Given e=1.6xx10^(-19) c , and m=9.1xx10^(-31) kg , the stopping potential is

The de-Broglie wavelength of proton (" charge" = 1.6 xx 10^(-19)C, "mass" = 1.6 xx 10^(-27) Kg) accelerated through a potential difference of 1kV is

The charge on the electron is 1.6 xx 10^(-19) C . The order of magnitude is

10 In Fig. 6.19, angled at and ll POR is at right triangle right angled os a Q and pk PO 6 cm and Ps s4em, find QS RS and OR. Fig. 6.19

A bar of iron is 10 cm at 20^(@)C . At 19^(@)C it will be (alpha_(Fe)=11xx10^(-6)//.^(@)C)

A 19.6 g of a given gaseous sample contains 2.8 g of molecules (d = 0.75 g L^(-1)) , 11.2 g of molecules (d = 3 g L^(-1)) and 5.6 g of molecules (d = 1.5 g L^(-1)) . All density measurements are made at STP . Calculate the total number of molecules (N) present in the given sample. Report your answer in 10^(23) N Assume Avogardro's number as 6 xx 10^(23) .