A particle starting from rest accelerates uniformly for 6s.If it covers a distance `S_1`in the first two second ,`S_2`in the next two second and` S_3` in the last two second ,then `S_1:S_2:S_3`

A particle starts moving from rest under uniform acceleration it travels a distance x in the first two seconds and a distance y in the next two seconds. If y=nx , then n=

A particle starts from the rest, moves with constant acceleration for 15s. If it covers s_1 distance in first 5s then distance s_2 in next 10s, then find the relation between s_1 & s_2 .

A body starts from rest and accelerates with 4 "m/s"^2 for 5 seconds. Find the distance travelled with 5 seconds.

A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels distance S_1 in the first 10 sec and a distance S_2 in the next 10 sec, Then

A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels distance S_1 in the first 10 sec and a distance S_2 in the next 10 sec, Then

A car starts from rest and accelerates uniformly to a speed of 180 kmh^(-1) in 10 s. The distance covered by the car in the time interval is

What will be ratio of speed in first two seconds to the speed in next 4s

A body starting from rest has an acceleration of 5m//s^(2) . Calculate the distance travelled by it in 4^(th) second.

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 s is s_1 and the covered in the first 20 s is s_2 , then.

A body starts from rest and is uniformly accelerated for 30 s. The distance travelled in the first 10 s is x_(1) , next 10 s is x_(2) and the last 10 s is x_(3) . Then x_(1):x_(2):x_(3) is the same as :-