`x = bSin^2(theta )`
`y = a Cos^2(theta )` then find `theta`

If x = 2sin^(2)theta and y = 2 cos^(2)theta+1 ,then find x+y

x sin ^ (3) theta + y cos ^ (3) theta = sin theta cos theta and x sin theta = y cos theta Find the value of x ^ (2) + y ^ (2)

If x sin^(3) theta + y cos^(3) theta = sin theta cos theta ne 0 and x sin theta - y cos theta = 0 , then value of (x^(2) + y^(2)) is :

If x sin^(3) theta + y cos^(3) theta = sin theta cos theta and x sin theta = y cos theta , then the value of x^(2) + y^(2) is :

If x= acos theta +bsin theta and y =bcos theta -asin theta then remove theta

If x = 3 sin theta + 4 cos theta and y = 3 cos theta - 4 sin theta then prove that x^(2) + y^(2) = 25 .