A sector of radius `12cm` with the central angle of `120^@` is folded to form a cone by joining the two bounding radii of the sector. What is the volume of the cone?

A sector of radius 10.5 cm with the central angle 120^@ is folded to form a cone by joining the two bounding radii of the sector. What is the volume (in cm^3 ) of the cone so formed ? 10.5 सेमी त्रिज्या वाला एक वृत्त खंड है जिसका केंद्रीय कोण 120^@ है | इसे मोड़कर वृत्त खंड की दो सीमांकन त्रिज्याओं को जोड़ कर एक शंकु का निर्माण किया जाता है | इस प्रकार निर्मित शंकु का आयतन ( घन सेमी में) क्या होगा ?

A sector of a circle of radius 6 cm and central angle 30^(@) is folded into a cone such that the radius of the sector becomes the slant height of the cone. What is the radius of the base of the cone thus formed?

A sector of a circle of radius 15 cm has the angle 120^(circ) . It is rolled up so that two bounded radii are joined together to form a cone. Find the volume of the cone. (Take pi = 22/7)

A right angled sector of radius r cm is rolled up into a cone in such a way that the two binding radii are joined together. Then the curved surface area of the cone is

The curved surface area of a right circular cone is 156pi and the radius of its base is 12 cm. What is the volume of the cone, in "cm"^(3) ?

The vertical angle of a right circular cone is a and the slant height is sqrt(2)r сm . What is the volume of the cone in cubic cm?