A large number of water drops each of radius r combine to have a drop of radius R. If the surface tension is T and mechanical equivalent of heat is J the rise in heat energy per unit volume will be

A number of droplets, each of radius r , combine to form a drop of radius R . If T is the surface tension, the rise in temperature will be

n number of water droplets, each of radius r , coalese, to form a single drop of radius R . The rise in temperature d theta is

The work done to blow a scap bubble of radius. R (surface tension T)

A certain number of spherical drops of a liquid of radius r coalesce to form a single drop of radius R and volume V . If T is the surface tension of the liquid, then

Two mercury drops each of radius r merge to form a bigger drop. Calculate the surface energy released.

Energy needed in breaking a drop of radius R into n drops of radius r, is where T is surface tension and P is atmospheric pressure.

A monoatomic gas at a temperature T has pressure P and heat energy per unit volume E. then

A large number of droplets, each of radius a, coalesce to form a bigger drop of radius b . Assume that the energy released in the process is converted into the kinetic energy of the drop. The velocity of the drop is sigma = surface tension, rho = density)

The energy needed for breaking a drop of radius R into n drops each of radius r is

A large number of liquid drops each of radius 'a' coalesce to form a single spherical drop of radius b. The energy released in the process is converted into kinetic energy of the big drops formed. The speed of big drop will be