The efficiency of a Carnot engine is 50% .If same system is used as heat pump , Then coefficient of performance of heat pump is

What is a heat pump ?

If the efficiency of a carnot engine is eta ,then the coefficient of performance of a heat pump working between the same temperatures will be

Efficiency of a Carnot heat engine may be given as

The maxium possible efficiency of a heat engine is

Define thermal efficiency of a heat engine.

The efficiency of Carnot's enegine is 50% . The temperature of its sink is 7^(@)C . To increase its efficiency to 70% . What is the increase in temperature of the source?

Efficiency of a heat engine working between a given source and sink is 0.5 . Coefficient of performance of the refrigerator working between the same source and the sink will be

If the efficiency of an engine is 50% and its work output is 500 J then find input.

The efficiency of a carnot engine is 40%, whose sink is at a temperature of 300 K. By how much should be temperature of the source be increased be get an efficiency of 60% ?

The efficiency of carnot engine is 50% and temperature of sink is 500K. If temperature of source is kept constant and its efficiency raised to 60%, then the required temperature of the sink will be : -