IF the relation between the magnitude of range R and time of flight T of a projectile is given as R=5`T^2` , Then value of angle of projection is
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The equations of motion of a projectile are given by x=36tm and 2y =96t-9.8t^(2)m . The angle of projection is

The equations of motion of a projectile are given by x=36t m and 2y =96t-9.8t^(2)m . The angle of projection is

The time of flight of a projectile is related to its horizontal range by the equation gT^2 = 2R . The angle of projection is

If the time of flight of a bullet over a horizontal range R is T, then the angle of projection with horizontal is -

The relation between the time of flight of projectile T_(f) and the time to reach the maximum height t_(m) is

If T_1 and T_2 are the times of flight for two complementary angles, then the range of projectile R is given by

What is the relationship between time of flight T and horizontal range R? (where theta is angle of projection with the horizontal)

If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is

When a particle is projected at an angle to the horizontal, it has range R and time of flight t_(1) . If the same projectile is projected with same speed at another angle to have the saem range, time of flight is t_(2) . Show that: t_(1)t_(2)=(2R//g)

A projectile has a range R and time of flight T. If the range is doubled (by increasing the speed of projection, without changing the angle of projection), the time of flight will become