Out of following the forward biased diode is: -4V -3V 3V 3V O OV -2V -2V 2V O

If the forward voltage in a semiconductor diode is chaged form 0.5 V to 2 V, then the forward current changed by 1.5 mA. The forward resistance of diode will be-

Find out the following a. V_A - V_B b. V_B - V_C c. V_C - V_A d. V_D - V_C e. V_A - V_D f. Arrange the order of potential for points (A, B,C and D). .

Solve the following system of equations: 8v-3u=5u v ,\ \ \ 6v-5u=-2u v

Give the magnitude and polarity of the following voltages in the circuit of figure: i. V_1 ii. V_2 iii. V_3 iv. V_(3-2) v. V_(1-2) V_(1-3)

A band playing music at a frequency f is moving towards a wall at a speed v_h . A motorist is following the band with a speed v_m . If v is the speed of sound, the expression for the beat frequency heard by the motorist is (n(V+V_m)V_b)/((V^2 - V_b^2)) . Then n

Three resistance are joined together to form a letter Y, as shown in figure. If the potentials of the terminals A, B and C are 6V, 3V and 2V respectively, then the potential of the point O will be

If the height and radius of a cone of volume V are doubled, then the volume of the cone, is (a) 3 V (b) 4 V (c) 6 V (d) 8 V

Assertion: Current flowing in the circuit is i=2t-8 . At t=1s, V_a-V_b=+4V Reason: V_a-V_b is +4 V all the time.

Solve the following system of equations: 2(3u-v)=5u v ,\ \ \ \ 2(u+3v)=5u v

If each edge of a cube, of volume V , is doubled, then the volume of the new cube is (a) 2 V (b) 4 V (c) 6 V (d) 8 V