Why ` Ce(OH)_(3)` is more basic than `Lu(OH)_(3)` ?

Assertion : La(OH)_(3) is more basic than Lu(OH)_(3) . Reason : Size of Lu^(3+) increases and shows more covalent character.

CsOH is more basic than Ba(OH)_(2) .

Explain the following : (a) Out of Sc^(3+), Co^(2+) " and "Cr^(3+) "ions, only "Sc^(3+) is colourless in aqueous solutions. (Atomic no.: Co =27, Sc = 21 and Cr =24) (b) The E^(@)Cu^(2+)//Cu for copper metal is positive (+0.34), unlike the remaining members of the first transition series. (c) La(OH)_(3) " is more basic than Lu "(OH)_(3).

STATEMENT-1 : Lu(OH)_(3) is more basic than Ce(OH)_(3) and STATEMENT-2: Lu^(+3) has smaller size than Ce^(+3)

A: La(OH)_(3) , is less basic than Lu(OH)_(3) , R: Basic character of hydroxides of lanthanoids increase on moving from La^(+3) to Lu^(+3)

State True/False La(OH)_3 is less basic than Lu(OH)_3

Which out of the two , La(OH)_(3) and Lu(OH)_(3) , is more basic and why?

Which of the following are not more basic than Al(OH)_(3) ?

Which is more basic La(OH)_(3) zor Lu(OH)_3 ? Why?

Tl(OH)_3 is less basic than TlOH . Why ?