Evaluate for `theta`
`Sin^4(theta ) + Cos^4(theta ) = 7/2 Sin(theta)Cos(theta)`

Show : Sin^4theta - Cos^4theta = Sin^2theta - Cos^2theta

sin^(4)theta+cos^(4)theta=1-2sin^(2)theta cos^(2)theta

"(i) "sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta

Prove that sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta

Prove that (sin^(4)theta-cos^(4)theta)/(sin^(2)theta-cos^(2)theta)=1

4 sin theta * cos^(3) theta-4 cos theta * sin ^(3)theta= A) 4 cos theta B) cos 4 theta C) 4 sin theta D) sin 4 theta

Prove that : cos^(4)theta - cos^(2)theta = sin^(4)theta - sin^(2) theta

Solve cos^(4)theta-sin^(4)theta=cos^2theta

Evaluate : sin theta cos theta - (sin theta cos (90^(@) - theta) cos theta)/( sec (90^(@) - theta)) - (cos theta sin (90^(@) - theta) sin theta)/( cosec (90^(@) - theta))