Evaluate for `theta`

`( aSintheta - bCostheta ) / ( aSintheta + bCostheta ) = ( a^2 - b^2 ) / ( a^2 + b^2 )`

If cottheta=(b)/(a) ,show that (asintheta-bcostheta)/(asintheta+bcostheta)=(a^(2)-b^(2))/(a^(2)+b^(2)) .

If btantheta=a , the value of (asintheta-bcostheta)/(asintheta+bcostheta) (a) (a-b)/(a^2+b^2) (b) (a+b)/(a^2+b^2) (c) (a^2+b^2)/(a^2-b^2) (d) (a^2-b^2)/(a^2+b^2)

If ((asintheta-bcostheta)/(asintheta+bcostheta))=((a^2-b^2)/(a^2+b^2))^k and tan theta=a/b then k=

If tan theta=(a)/(b), prove that (a sin theta-b cos theta)/(a sin theta+b cos theta)=(a^(2)-b^(2))/(a^(2)+b^(2))

If tan theta=(a)/(b), show that (a sin theta-b cos theta)/(a sin theta+b cos theta)=(a^(2)-b^(2))/(a^(2)+b^(2))

If asintheta+bcostheta=c , find acostheta-bsintheta=?

Evaluate (a+bcostheta)^2+(bsintheta)^2

If x = a cos theta - b sin theta and y = a sin theta + b cos theta, prove that x^2 + y^2 = a^2 + b^2.

If tan theta=(a)/(b) such that (a sin theta-b cos theta)/(a sin theta+b cos theta)=(a^(2)-b^(2))/(a^(2)+b^(2))^(k) then k is ?

If a tan theta = b, then a cos 2 theta+ b sin 2 theta =