cos^(-1)cos(-5)+sin^(-1)sin(6)-tan^(-1)tan(12) is equal to:(The inverse trigonometric functions take

cos(tan^(-1)3/4)+cos(tan^(-1)x) is equal to

If alpha=3sin^-1(6/11) and beta=3cos^-1(4/9) , where the inverse trigonometric functions take only the principal values, then the correct option(s) is (are)

tan^-1[(cos x)/(1+sin x)] is equal to

The value of cot [sin^(-1){cos(tan^(-1)1)}] is

The value of cot [sin^(-1){cos(tan^(-1)1)}] is

The value of sin^(-1) (sin 12) + cos^(-1) (cos 12) is equal to

If [sin ^(-1)(cos^(-1)(sin^(-1)(tan^( -1)x)))]=1 where [.] denotes integer function, then complete set of values of x is :

Solve : tan(cos^(-1) x) = sin (tan^(-1) 2)

If [sin^-1 (cos^-1(sin^-1 (tan^-1 x)))]=1 , where [*] denotes the greatest integer function, then x in

Find the value of the following inverse trigonometric expression: tan^(-1)(tan(-6))