Consider the equation `x^2+2x-n=0`, `n in N` and `n in [5,100]`, the number of different of `n` so that the given equation has integral roots is

Consider the equation x^(2)+2x-n=0 where n in N and n in[5,100] The total number of different values of n so that the given equation has integral roots is a.8 b.3 c. 6d.4

Consider the equation x^(2) + 2x - n = 0 m where n in N and n in [5, 100] . The total number of different values of n so that the given equation has integral roots is

Consider the equation x^(3)-nx+1=0, n in N, n ge 3 . Then

consider the equation x^(2)+x-n=0 where a is an integer lying between 1 to 100. Total number of different values of n so that the equation has integral roots,is

Roots of the equation x^(n)-1=0,n in I

The number of integral values of n such that the equation 2n{x}=3x+2[x]has exactly 5 solutions.

Consider the cubic equation f(x)=x^(3)-nx+1=0 where n ge3, n in N then f(x)=0 has

Consider the equation (2)/(x)+(5)/(y)=(1)/(3) where x,y in N. Find the number of solutions of the equation.

If n is a positive integer and n in[5,100] then the number of positive integral roots of the equation x^(2)+2x-n=0 is

The maximum number of real roots of the equation x^(2n) -1 = 0 , is