Evaluate `costheta[[costheta,-sintheta],[sintheta,costheta]]+sintheta[[sintheta,costheta],[-costheta,sintheta]]`

Show that costheta [[costheta, sintheta],[-sintheta, cos theta]] + sin theta [[sintheta ,-cos theta],[costheta, sin theta]] =1

Simplify costheta[costhetasinthetasinthetacostheta]+sintheta[sintheta-costhetacosthetasintheta]

Show that costheta.[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta.[{:(sintheta,-costheta),(costheta,sintheta):}]=I.

costheta[{:(costheta,-sin theta),(sintheta,costheta):}]+sintheta[{:(sintheta,costheta),(-costheta,sintheta):}]=?

Evaluate costheta/sintheta

Evaluate sintheta/costheta

Evaluate- |[costheta,sintheta],[sintheta,costheta]|

Simplify: cos theta[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta[{:(sin theta ,-costheta),(costheta, sintheta):}]

costheta[(costheta, sintheta),(-sintheta,costheta)]+sintheta[(sintheta,-costheta),(costheta,sintheta)] is equal to (A) [(0,0),(1,1)] (B) [(1,1),(0,0)] (C) [(0,1),(1,0)] (D) [(1,0),(0,1)]

If A=[[costheta, sintheta], [-sintheta, costheta]] , then