Home
Class 11
MATHS
Prove that the equation to the parabola,...

Prove that the equation to the parabola, whose vertex and focus are on the axis of x at distances a and a' from the origin respectively, is is `y^(2) = 4 (a'-a) (x-a)`

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of parabola whose vertex and focus lie on the axis of x at distances a and a_1 from the origin respectively, is

What is the equation of the parabola, whose vertex and focus are on the x-axis at distance a and b from the origin respectively ? (bgtagt0)

The equation of the parabola whose vertex and focus lie on the axis of x at distances a and a_(1) from the origin,respectively,is y^(2)-4(a_(1)-a)xy^(2)-4(a_(1)-a)(x-a)y^(2)-4(a_(1)-a)(x-a)1) none of these

P is parabola,whose vertex and focus are on the positive x axis at distances a and a 'from the origin respectively,then (a'>a). Length of latus ractum of P will be

The equation of the parabola whose vertex is at(2, -1) and focus at(2, -3), is

Find the equation of a parabola whose vertex is (-2,0) and focus is (0,0).

The equation of parabola whose vertex and focus are (0,4) and (0,2) respectively, is