A tangent to the parabola `y^(2) = 8x` makes an angle of `45^(@)` with the straight line `y = 3x + 5`. Find its equation and its point of contact.

A tangent to the parabola y^(2)=8x makes an angle of 45^(@) with the straight line y=3x+5 Then points of contact are.

A tangent to the parabola y^(2)=8x makes an angle of 45^(@) with the straight line y=3x+5 Then find one of the points of contact.

The equation of a tangent to the parabola y^(2)=8x which makes an angle 45^(@) with the line y = 3x + 5 is

Equation of a tangent to the parabola y^(2)=12x which make an angle of 45^(@) with line y=3x+77 is

If the normal chord of the parabola y^(2)=4 x makes an angle 45^(@) with the axis of the parabola, then its length, is

On the parabola y^(2)=64x , find the point nearest to the straight line 4x + 3y - 14 = 0.

The equation of a tangent to the parabola, x^(2) = 8y , which makes an angle theta with the positive direction of x-axis, is:

Two tangents to the parabola y^(2) = 8x meet the tangent at its vertex in the points P & Q. If PQ = 4 units, prove that the locus of the point of the intersection of the two tangents is y^(2) = 8 (x + 2) .