If a normal to a parabola make an angle `phi` with the axis, show that it will cut the curve again at an angle `tan^(-1) ((1)/(2) tan theta)`

If a normal to a parabola y^(2)=4ax makes an angle phi with its axis,then it will cut the curve again at an angle

If the normal to a parabola y^2=4ax , makes an angle with the axis then it will cut the curve again at an angle.

Two equal parabola have the same vertex and their axes are at right angles. Prove that they cut again at an angle tan^(-1) 3/4 .

If the normal chord of the parabola y^(2)=4 x makes an angle 45^(@) with the axis of the parabola, then its length, is

If two normals drawn from any point to the parabola y^(2) = 4ax make angle alpha and beta with the axis such that tan alpha . tan beta = 2, then find the locus of this point,

Two tangents to parabola y ^(2 ) = 4ax make angles theta and phi with the x-axis. Then find the locus of their point of intersection if sin (theta - phi) =2 cos theta cos phi.

If the normal to the curve x^((2)/(3))+y^((2)/(3))=a^((2)/(3)) makes an angle phi with the x-axis,show that its equation is,y cos phi-x cos phi=a cos2 phi

A normal to parabola, whose inclination is 30^(@) , cuts it again at an angle of