Two particles A and B are performing SHM with same angular frequency `(omega)` same amplitude `(A_(0))` along same line about same mean position O. At t=0 ,particle's positions are shown in figure. Particles will cross each other at `t=(n pi)/(24 omega)` Value of n is

Two particles are performing SHM in same phase. It means that

A particle of mass m executing SHM with angular frequency omega_0 and amplitude A_0 , The graph of velocity of the particle with the displacement of the particle from mean position will be (omega_0 = 1)

two partical excuting SHM with same frequency and amplitudes A and 2A on same straight line with same mean position cross each other in opposite direction at a distance A//3 from mean possion. Find the phase difference in the two SHM s.

Two particles execute SHM of same amplitude and same time period, about same mean position but with a phase difference between them. At an instant they are found to cross each other at x=+(A)/(3) . The phase difference between them is

Two particles A and B are revolving with constant angular velocity on two concentric circles of radius 1m and 2m respectively as shown in figure. The positions of the particles at t = 0 are shown in figure. The positions of the particles at t=0 are shown in figure. if m_(A)=2kg, m_(B)= 1kg and vec(P)_(A) and vec(P)_(B) are linear momentum of the particle then what is the maximum value of |vec(P)_(A)+vec(P)_(B)| in kg-m/sec in subsequent motion of two particles.

Two particles are in SHM with same amplitude A and same regualr frequency omega . At time t=0, one is at x = +A/2 and the other is at x=-A/2 . Both are moving in the same direction.

Two particles undergo SHM along parallel lines with the same time period (T) and equal amplitudes. At particular instant, one particle is at its extreme position while the other is at its mean position. The move in the same direction. They will cross each other after a further time.

Two particles P_(1) and P_(2) are performing SHM along the same line about the same mean position , initial they are at their extreme position. If the time period of each particle is 12 sec and the difference of their amplitude is 12 cm then find the minimum time after which the separation between the particle becomes 6 cm .

Two particle P and Q describe S.H.M. of same amplitude a same frequency f along the same straight line .The maximum distance between the two particles is asqrt(2) The phase difference between the two particle is

Two particle P and Q describe S.H.M. of same amplitude a same frequency f along the same straight line .The maximum distance between the two particles is asqrt(2) The phase difference between the two particle is