Find the integral
`I=int cosx/(cos3x)dx`

int (cosx)/(cos 3x)dx

int (cos2x)/(cosx) dx=

Consider the integrals I=int(sinx)/(3cos x+4sinx)dx and J=int(cosx)/(3cos x+4sinx)dx . Then, the integral 4J-3J is equal to (where, c is the constant of integration)

Evaluate the following integrals: int(cos2x)/(cosx)dx

Find the integration int(sin2x cos x.dx)

Evaluate the following integrals: int(cos x)/(1-cos x)dx

Evaluate the following integrals: int(cosx)/(cos(x+alpha))dx

Integrate: int (dx)/(2+cosx)

Evaluate the following integrals: int (1-cos x)/(sin x) dx