1.The velocity of a body of mass 20kg decreases from 20m/s to 5m/s in a distance of 100m Force on the body is-
1) -27.5 N
2) -47.5 N
3) -37.5 N
4) -67.5 N

A uniform force of 4 N acts on a body of mass 10 kg for a distance of 2.0 m . The kinetic energy acquired by the body is

A force of 10 N acts on a body of mass 0.5 kg for 0.25s starting from rest.What is its momentum now?

A force of 10 N acts on a body of mass 2 kg for 3s , initially at rest. Calculate the velocity acquired by the body

A body of mass 5 kg is raised vertically to a height of 10 m by a force 170 N. The velocity of the body at this height will be

The weight of a body is 2.0 N. What is the mass of the body ? (g = 10 m s^(-2) )

A body of mass 5 kg is taken a height 5 m to 10 m .Find the increase in its potential energy (g=10 m s^(-2) )

Certain force acting on a 20 kg mass changes its velocity from 5m//s to 2m//s . calculate the work done by the force.

A body of mass 2 kg starts with an intitial-velocity 5 m/s. It the body is acted upon by a time dependent force (F) as shown in figure, then work done on the body in 20 s is A. − 875 J B. 875J C. 600J D. − 600 N J

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The velocity acquired by the body

A force acts for 10 s on a stationary body of mass 100 kg, after which the force ceases to act. The body moves through a distance of 100 m in the next 5 s. Calculate: The magnitude of the force.