`[[1,2],[4,3]][[-lambda,0],[0,-lambda]]=0`; find `lambda`.

[" 2.Let matrix "A=[[1,y,4],[2,2,z]]" ; if "xyz=2 lambda" and "8x+4y+3z=lambda+28," then "(adj A)" A equals: "],[[" (A) "[[lambda+1,0,0],[0,lambda+1,0],[0,0,lambda+1]]," (B) "[[lambda,0,0],[0,lambda,0],[0,0,lambda]]],[" (C) "[[lambda^(2),0,0],[0,lambda^(2),0],[0,0,lambda^(2)]]," (D) "[[lambda+2,0,0],[0,lambda+2,0],[0,0,lambda+2]]]]

If the matrix [[0,1,-2],[-1,0,3],[lambda,-3,0]] is singular,then lambda=

For a non zero " lambda" ,the value of matrix "[[lambda,1,0],[0,lambda,1],[0,0,lambda]]^(n) " is equal to

A=[[2-lambda,-1,0-1,2-lambda,-10,-1,2-lambda]] then find out

If a lambda^(4)+b lambda^(3)+c lambda^(2)+d lambda+e=|[lambda^(2)-3,lambda-1,lambda+sqrt(3)],[lambda^(2)+lambda,2 lambda-4,3 lambda+1],[lambda^(2)-3 lambda,3 lambda+5,lambda-3]| then |a| equals

If |[lambda^(2)+3 lambda,lambda-1,lambda+3],[lambda+1,2-lambda,lambda-4],[lambda-3,lambda+4,3 lambda]|=p lambda^(4)+q lambda^(3)+r lambda^(2)+s lambda+t then t=

If a lambda^(4)+b lambda^(3)+c lambda^(2)+d lambda+e = |[lambda^(2)-3,-1,lambda+sqrt(3)],[lambda^(2)+lambda,2 lambda-4,3 lambda+1],[lambda^(2)-3 lambda,3 lambda+5,lambda-3]| then |a| equals

Let A=[[x+lambda,x,x] , [x,x+lambda,x] ,[x,x,x+lambda]] then A^(-1) exists if (A) x!=0 (B) lambda!=0 (C) 3x+1!=0 , lambda!=0 (D) x!=0 , lambda!=0

If |[lambda^(2),-lambda,2 lambda-1],[lambda+2,1-lambda,lambda],[lambda+2,lambda+1,-lambda]|=a lambda^(4)+b lambda^(3)+c lambda^(2)+d lambda+e Then values of a, b, c, d and e are.

lambda ^ (3) -6 lambda ^ (2) -15 lambda-8 = 0