Find the value of x as subject :
`1/x + 1/y = 5`

Find the value of ( 1/x + 1/y ) ( 1/x - 1/y )

Find the value of x : -1/5 = 2/x

Find the value of ( 1/x + 1/y ) ( 1/x - 1/y ) ( 1/x^2 + 1/y^2 )

x+(1)/(x)=5 Find the value of x

Find the maximum value of x+y subjected to the condition 4x+3y le 12, 2x + 5y le 10, x le 0, x ge 0, y ge 0 .

If sec^(-1) x = cosec^(-1) y , then find the value of cos^(-1) . 1/x + cos ^(-1) . 1/y .

If Z=5x+3y ,then maximum value of Z ,subject to x =0,y>=0 is: