`int cos^(2)((x)/(2))dx`

Evaluate : int(1)/(x^(2)"cos"^(2)((1)/(x)))dx

int(cos^(2) (log .x))/(x)dx

If A = int_(0)^((pi)/(2))(sin^(3)x)/(1+cos^(2)s)dx and B=int_(0)^((pi)/(2))(cos^(2)x)/(1+sin^(2)x)dx , then (2A)/(B) is equal to

Evaluate: int(cos2x)/(2+sin2x)dx

int (cos^(2)x+sin 2x)/((2 cos x- sin x)^(2))dx

int sin2x*e^(cos^(2)x)dx

I=int(sin2x-cos2x)^(2)dx

int cos (2x +1) dx

1. int(cos(x/2))^2dx

Evaluate (i) int(cos2x+2sin^(2)x) dx