find `dy/dx`, if `x=cos^3theta`,`y=sin^3 theta `

Find dy/dx x=a\ cos^3theta , y=a\ sin^3theta

Find (dy)/(dx) if x= 3 cos theta - cos 2theta and y= sin theta - sin 2theta.

Find (dy)/(dx) if x=cos theta - cos 2 theta and" "y = sin theta - sin 2theta

Differentiate w.r.t x Given x =a cos^(3) theta , y = b sin^(3) theta

If x = a cos^(3) theta, y = a sin ^(3) theta then sqrt(1+((dy)/(dx))^(2)) =?

"Find "(dy)/(dx) if x =a(theta- sin theta) and y= a (1- cos theta).

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=costheta-cos2theta, y=sintheta-sin2theta

Find the slope of the normal to the curve x=a\ cos^3theta , y=a\ sin^3theta at theta=pi/4 .

Find the equation of normal to the curve x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.

Find the slopes of the tangent and the normal to the curve x=a\ cos^3theta,\ \ y=a\ sin^3theta at theta=pi//4