Which of the following is a false expression of electric power ?

Options

A. `P=VI`
B. `P = V^(2)//R`
C. `P = V +R`
D. `P = I^(2)R`

Explanation

To determine which of the given expressions for electric power is false, we can analyze each option based on the fundamental relationships in electric circuits.

### Step-by-Step Solution:

1. **Understanding Electric Power**:
Electric power (P) can be defined in terms of voltage (V) and current (I) using the formula:
\[ P = V \times I \]

2. **Evaluating the Options**:
- **Option 1: \( P = VI \)**
- This is a correct expression for electric power.
- **Option 2: \( P = \frac{V^2}{R} \)**
- This expression can be derived from Ohm's Law, where \( V = IR \). Substituting \( I = \frac{V}{R} \) into \( P = VI \) gives:
\[ P = V \left(\frac{V}{R}\right) = \frac{V^2}{R} \]
- Thus, this option is also correct.
- **Option 3: \( P = V + R \)**
- This expression does not follow from any known relationship in electric power. There is no formula that relates power directly to the sum of voltage and resistance. Hence, this is likely the false expression.
- **Option 4: \( P = I^2 R \)**
- This can also be derived from Ohm's Law. By substituting \( V = IR \) into \( P = VI \):
\[ P = I(IR) = I^2 R \]
- Therefore, this option is correct as well.

3. **Conclusion**:
After evaluating all options, we find that:
- The false expression for electric power is **Option 3: \( P = V + R \)**.

### Final Answer:
The false expression of electric power is **Option 3: \( P = V + R \)**.