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In Wheatstone bridge, three resistors P,...

In Wheatstone bridge, three resistors P,Q and R connected in three arms in order and 4th arm of resistance s, is formed by two resistors `s_(1)` and `s_(2)` connected in parallel. The condition for bridge to be balanced is, `(P)/(Q)`

A

`(P)/(Q)=(R(S_(1)+S_(2)))/(2S_(1)S_(2))`

B

`(P)/(Q) = (R )/(S_(1)+S_(2))`

C

`(P)/(Q) =(2R )/(S_(1) +S_(2))`

D

`(P)/(Q) =(R(S_(1)+S_(2)))/(S_(1)S_(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
Equivalent resistance of the parallel combination of `S_(1) and S_(2)` is
`S=(S_(1)S_(2))/(S_(1)+S_(2))`
For the balanced wheatstone bridge,
`(P)/(Q)=(R )/(S) =(R (S_(1)+S_(2)))/(S_(1) S_(2))`
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