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A uniform magnetic field is at a right a...

A uniform magnetic field is at a right angle to the normal of the plane surface. Find the value of magnetic flux?

A

`phi=1.5`

B

`phi = 0`

C

`phi=1`

D

`phi=-1`

Text Solution

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The correct Answer is:
To find the value of magnetic flux when a uniform magnetic field is at a right angle to the normal of a plane surface, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Magnetic Flux**: Magnetic flux (Φ) through a surface is defined as the product of the magnetic field (B) and the area (A) of the surface, multiplied by the cosine of the angle (θ) between the magnetic field and the normal (perpendicular) to the surface. \[ \Phi = B \cdot A \cdot \cos(\theta) \] 2. **Identify the Given Information**: - The magnetic field is uniform. - The magnetic field is at a right angle (90 degrees) to the normal of the plane surface. 3. **Determine the Angle (θ)**: Since the magnetic field is at a right angle to the normal of the surface, the angle θ is 90 degrees. 4. **Substitute the Angle into the Formula**: Substitute θ = 90° into the magnetic flux formula: \[ \Phi = B \cdot A \cdot \cos(90°) \] 5. **Evaluate Cosine of 90 Degrees**: The value of cos(90°) is 0. \[ \Phi = B \cdot A \cdot 0 \] 6. **Calculate Magnetic Flux**: Since any number multiplied by 0 is 0, we find: \[ \Phi = 0 \] ### Final Answer: The value of magnetic flux (Φ) is 0. ---

To find the value of magnetic flux when a uniform magnetic field is at a right angle to the normal of a plane surface, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Magnetic Flux**: Magnetic flux (Φ) through a surface is defined as the product of the magnetic field (B) and the area (A) of the surface, multiplied by the cosine of the angle (θ) between the magnetic field and the normal (perpendicular) to the surface. \[ \Phi = B \cdot A \cdot \cos(\theta) ...
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