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The maximum value of the function define...

The maximum value of the function defined by `f(x)=min(e^x,2+e^2-x,8)` is `alpha` , then integral values of x satisfying the inequality `frac{x(x-[alpha])}{x^2-[alpha]x+12}`< 0 , is :
( Note: [k] denotes greatest integer less then or equal to k.)

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