`24g` of carbon (graphite) is completely reacted with `38.4gm` of oxygen and form `CO` and `CO_(2)` gases at STP, then the ratio of moles of `CO_(2)` & `CO` formed is `X:1`. The value of `X` is

4.4 g of CO_(2) contains how many litres of CO_(2) at STP ?

The volume of CO_(2) at STP obtained by heating 1 g of CaCO_(3) will be

2 moles carbon and 1.5 moles of oxygen gas are reacted in a container to produced CO and CO_(2) or both such that none of reactant is left. Find moles of CO, CO_(2) produced.

How many litres of CO_(2) gas at STP will react with 2.5 moles of KOH exactly to form K_(2)CO_(3) ?

X litre of carbon monoxide is present at STP. It is completely oxidised to CO_2 formed is 11.207 L. What is the value of X in litres?

When 12.0g of carbon (graphite)reacted with oxygen to form CO and CO_(2) at 25^(@)C and constant pressure, 252 kJ of heat was released and no carbon remained. If Delta H_(f)^(0)(CO,g)= -110.5 kJ mol^(-1) and Delta H_(f)^(0)(CO_(2),g)= -393.5 kJ mol^(-1) ,calculate the mass of oxygen consumed.

Calculate the volume occupied at S.T.P. by 2 moles of CO_(2)

The volume of CO_(2) obtained by the complete decomposition of one mole of NaHCO_(3) at STP is

When 80 gm CH_(4) is burnt completely , CO and CO_(2) gases are formed in 1:4 mole ratio. What is the mass of O_(2) gas used in combustion.

On heating a mixture containing 1 mole each of Li_(2)CO_(3) and K_(2)CO_(3), x mole of CO_(2) is//are formed. Find the value of x.