Simplify
`1/(1+2omega)+1/(2+omega)-1/(1+omega)`

(1)/(2+omega)+(1)/(1+2 omega)=(1)/(1+omega)

(1)/(2+omega)+(1)/(1+2 omega)=(1)/(1+omega)

(1)/(1+2 omega)+(1)/(2+omega)-(1)/(1+omega)=0

If omega be an imaginary cube root of unity, show that: 1/(1+2omega)+ 1/(2+omega) - 1/(1+omega)=0 .

If omega be a complex cube root of unity then the value of (1)/(1+2 omega)-(1)/(1+omega)+(1)/(2+omega) is

(1)/(1+2 omega)-(1)/(1+omega)+(1)/(2+omega)= 1. omega\*2. omega^(2) \* 3. a^(2)+b^(2) \*4. 0

If omega_(1) is complex cube root of that (1)/(a+omega)+(1)/(b+omega)+(1)/(c+omega)=2 omega^(2) and (1)/(a+omega^(2))+(1)/(b+omega^(2))+(1)/(c+omega^(2))=2 omega then the value of (1)/(a+1)+(1)/(b+1)+(1)/(c+1)=