`int((1-tan (x/2))/(1+tan (x/2)))dx`

int (1-tan^2x)/(1+tan^2x) dx

The value of int_(0) ^(2pi) cos ^(-1) ((1- tan ^(2) ""(x)/(2 ))/(1+ tan ^(2)""(x)/(2))) dx is:

int(sec x)/(tan^(2)x)dx

Evaluate: int(tanxsec^2x)/(1-tan^2x)dx

Evaluate: int(tan^2xsec^2x)/(1+tan^6x)dx

(i) int(1)/((1+x^(2))tan ^(-1) x )dx " "(ii) int(e^(tan^(-1)x))/(1+x^(2))dx

int (tan^(-1)x)dx

int(1)/(sqrt(1-tan^(2)x))dx

Evaluate: int e^(x) (1 + tan x + tan^(2)x)dx

The value of int (tan x )/(tan ^(2) x + tan x+1)dx =x -(2)/(sqrtA) tan ^(-1) ((2 tan x+1)/(sqrtA))+C Then the value of A is: