Light of wavelength `0.6 mu m` from a sodium lamp falls on a photocell and causes the emission of photoelectrons for which the stopping potential is `1.5V` .With this data, the value of `h/e` is `(n times10^(-15))V_(S)` .Find value of `n`

Light of wavelength 0.6 mum from a sodium lamp falls on a photocell and causes the emission of photoelectrons for which the stopping potential is 0.5 V. With wavelength 0.4 mum from a sodium lamp, the stopping potential is 1.5 V. With this data , the value of h/e is

Light of wavelength 0.6mum from a sodium lamp falls on a photocell and causes the emission of photoelectrons for which the stopping potential is 0.5V. With light of wavelength 0.4mum from a murcury vapor lamp, the stopping potential is 1.5V . Then, the work function [in electron volts] of the photocell surface is

What amount of energy sould be added to an electron to reduce its de Broglie wavelength lamda_1=550nm incident on it, causing the ejection of photoelectrons for which the stopping potential is V_(s1)=0.19V . If the radiation of wavelength lamda_2=190nm is now incident on the surface, (a) calculate the stopping potential V_(S2) , (b) the work function of the surface, and (c) the threshold frequency for the surface.

When a yellow light of wavelength 6000Å from a sodium lamp falls on a certain photocell, a negative potential of 0.30 volt is needed to stop all the electtons from reaching the collector. Then choose correct option (s)

The work function of Cs is 2.14 ev find the wavelength of the incident light if the stopping potential is 0.6 V.

Light falls from glass (mu=1.5) to air. Find the angle of incidence for which the angle of deviation is 90^@ .

For intensity I of a light of wavelength 5000 Å the photoelectron saturation current is 0.40 mu A and stopping potential is 1.36 V , the work function of metal is

The work function of a photoelectric material is 4.0 e V. (a) What is the threshold wavelength? (b) find the wavelength of light for which the stopping potential is 2.5 V.

The work function of a metal is 3.0 V. It is illuminated by a light of wave length 3 xx 10^(-7)m . Calculate i) threshold frequency, ii) the maximum energy of photoelectrons, iii) the stopping potential. (h=6.63 xx 10^(-34)Js and c=3 xx 10^(8)ms^(-)) .

a. A stopping potential of 0.82V is required to stop the emission of photoelectrons from the surface of a metal by light of eavelength 4000 A . For light of wavelength 3000 A , the stopping potential is 1.85V . Find the value of Planck's constant. [1 electrons volt (eV) =1.6xx10^(-19)J] b. At stopping potential, if the wavelength of the incident light is kept fixed at 4000 A , but the intensity of light increases two times, will photoelectric current be botained ? Give reasons for your answer.