ax+by=2 : bx+ay=3

ax + by = c bx+ ay =1 +c

Find the value of x and y: ax +by =a-b bx-ay =a+b

A, B C and D are the points of intersection with the coordinate axes of the lines ax+by=ab and bx+ay=ab, then

The base BC of a triangle ABC is bisected at the point (a, b) and equation to the sides AB and AC are respectively ax+by=1 and bx+ay=1 Equation of the median through A is:

If a gt b gt c and the system of equtions ax +by +cz =0 , bx +cy+az=0 , cx+ay+bz=0 has a non-trivial solution then both the roots of the quadratic equation at^(2)+bt+c are

If a !=b , then the system of equation ax + by + bz = 0 bx + ay + bz = 0 and bx + by + az = 0 will have a non-trivial solution, if

The the area bounded by the curve |x| + |y| = c (c > 0) is 2c^(2) , then the area bounded by |ax + by| + |bx - ay| = c where b^(2) - a^(2) = 1 is

Factorise : (v) (ax + by )^(2) + (bx - ay)^(2)

Factorise : xy - ay - ax + a^2 + bx - ab

{:(ax + by = 1),(bx + ay = ((a + b)^(2))/(a^(2) + b^(2))-1):}