if x:y= 7:5 and y:z = 4:4 find x:z

If X: Y = 2:3 and Y:Z = 3:4 find X:Z .

Find the values of x, y and z from the following equations:(i) [[4, 3],[x,5]]=[[y, z],[1, 5]] (ii) [[x+y,3],[ 5+z, x y]]=[[6, 3],[ 5 ,8]] (iii) [[x+y+z],[ x+z],[ y+z]]=[[9],[ 5],[ 7]]

Write the values of x,y and z from the following equation: [[x+y+z],[ x+z],[ y+z]]=[[9], [5], [7]]

If X = 5Y = 8Z, find X:Y:Z.

The planes 2x + 5y + 3z = 0, x-y+4z = 2 and7y-5z + 4 = 0

find the values of x,y and zfrom the following equations : (i) [{:(4,3),(x,5):}]=[{:(y,z),(1,5):}] (ii) [{:(x+y,2),(5+z,xy):}]=[{:(6,2),(5,8):}] (iii) [{:(x+y+z),(x+z),(y+z):}]=[{:(9),(5),(7):}]

Let x ,y ,z in R such that x+y+z=6a nd x y+y z+z x=7. Then find the range of values of x ,y ,a n dzdot

Subtract 12x + 3y - z from the sum of 7x + 4y - 5z + 5 and 6x - 7z - 8 .

If x=4z^2+5,\ \ y=6z^2+7z+3, find (d^2y)/(dx^2) .