Simplify the following term
`sin^6theta+cos^6theta`

Prove the following identities: 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1=0sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1(sin^(8)theta-cos^(8)theta)=(sin^(2)theta-cos^(2)theta)(1-2sin^(2)theta cos^(2)theta)

Simplify sin^8theta-cos^8theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

The value of the following is : 3(sin^(4)theta+cos^(4)theta)+2(sin^(6)theta+cos^(6)theta)+12sin^(2)thetacos^(2)theta

If sin theta-cos theta=0 then find the value of sin^6theta+cos^6theta

If sin theta+cos theta=(5)/(4) then find the value of sin^(6)theta+cos^(6)theta+7sin^(2)theta*cos^(2)theta

sin ^ (6) theta + cos ^ (6) theta =

If sin theta cos theta = 1//2, then what is sin^6 theta +cos^6 theta equal to?

What is the value of sin^6 theta + cos^6 theta + 3sin^2 theta cos^2 theta ?