In a standard YDSE setup, the fringe width on the screen is `1.5mm` .When a thin glass film is pasted in front of the upper slit, the fringe pattern shifts up. But it is seen that at a point `P` above central maxima where intensity was one fourth the intensity at central maxima, intensity remains the same. There were no maxima between central maxima and point `P` before film was introduced. What can be the thickness of the film? Take `mu=1.5`, `lambda=450nm`

In YDSE intensity at central maxima is I_0 The ratio I/I_0 , at path difference lamda/8 on the screen from central maxima , is closed to

Statement-1: In YDSE, if a thin film is indroduced in front of the upper slit then the fringe pattern shifts in the downward direction. Statement-2: in YDSE if the slit widths are unequal the minima will be completely dark.

Find the ratio of the intensities of the secondary maxima to the intensity of the central maximum for the single slit Fraunhofer diffraction pattern.

In a Young's double slit experiment, I_0 is the intensity at the central maximum and beta is the fringe width. The intensity at a point P distant x from the centre will be

In a Young's double slit experiment, I_0 is the intensity at the central maximum and beta is the fringe width. The intensity at a point P distant x from the centre will be

In a Young's double slit experiment, I_0 is the intensity at the central maximum and beta is the fringe width. The intensity at a point P distant x from the centre will be

The path difference between two interfering waves at a point on the screen is lambda"/"6 from central maximum. The ratio of intensity at this point and that at the central fringe will be

In YDSE of equal width slits, if intensity at the center of screen is I_(0) , then intensity at a distance of beta // 4 from the central maxima is

In a YDSE using monochromatic visible light, the distance between the plate of slits and the screen is 1.7 m. At point P on the screen which is directly in front of the upper slit, maximum path is observed. Now, the screen is moved 50 cm closer to the plane of slits. Point P now lies between third and fouth minima above the central maxima and the intensity at P in one-fourth of the maxima intensity on the screen. ltbr. Find the wavelength of light if the separation of slits is 2 mm.

In a YDSE with identical slits, the intensity of the central bright fringe is I_(0) . If one of the slits is covered, the intensity at the same point is